Notes
-
Reaction Stoichiometry: mass relationships between reactants and products in a chemical reaction
-
Mole Ratio: conversion factor that relates amount in moles of two substances in chemical reaction
- Coefficients convey ratio of substances needed for the reaction to occur (in terms of moles)
- One mole water = 18 grams; 1 molecule of water = 18 amu
- Oxygen Ratio: 1 mole = 16 grams = 6.02 x 10^23 atoms
- Round up to 100th place
- Ex: 4:5:6:4 can mean 4 molecules react with 5 molecules to produce 6 molecules and 4 molecules
Molar Mass
Molar Mass of a Compound
-
Determine how many of each atom
-
Multiply each element’s number of atoms by atomic mass
-
Add up total mass to find molar mass (don’t forget to write grams/mol)
Molar Mass of a Compound Containing Polyatomic Ions
-
-
Number under parenthesis belongs to ALL atoms so multiply to find how many
-
Determining the Formula of a Compound
-
-
Molecular Formula: the actual number of atoms of each element in a compound
-
Ex: C6H12O6
-
-
Empirical Formula: the lowest whole number ratio of elements
-
Ex: : CH2O
-
-
Determining Empirical and Molecular Formula for a Compound
- Use process when asked to find subscripts of an element in compound
- Multiply given percent with element’s molar mass to find gram of element → convert grams into moles (divide each element by atomic mass) → divide by lowest number of moles = empirical formula
- If given only percentages, assume 100g sample and convert to grams → follow above steps
- If you do not have a whole number, multiply by the smallest whole # to get a whole # ratio → whole #s = subscripts for each element
- To find the molecular formula, divide the molecular molar mass by the empirical molar mass. Then multiply each of the subscripts by that answer
Empirical Formula on the AP Exam
-
- Straightforward mass or % composition data
- Combustion analysis: burning a sample in O2 and analyzing products to determine relative amounts of C and H
- Hydrate analysis: heating hydrated ionic solid and analyzing mass change to determine mole ratio of water to solid
- Hydrate is heated → water is driven off → mass of sample decreases; hydrate is no longer a hydrate when mass is not decreasing
- To determine formula of hydrated compound → determine moles of water → determine moles of hydrate → find ratio of moles of water / moles of compound → answer equals the number of H2O
The Meaning of a Chemical Equation
- The chemical equation for a reaction gives 2 types of info: the nature of the reactants and products and the relative numbers of each.
Balancing Chemical Equations
- Atoms are conserved in a chemical reaction.
- Only the coefficients can be changed; the subscripts in a formula cannot be changed, nor can atoms be added or subtracted from a formula.
- Process in balancing elements: Metals → Nonmetals → Hydrogen → Oxygen
For Combustion Reactions (Fuel + O2 → CO2 + H2O)
- Balance carbon → hydrogen
- Count the number of oxygen atoms on the right
- Take half that number and make it the coefficient of the oxygen on the left
- If you now have a fraction, multiply all coefficients by 2
Stoichiometric Calculations: Amounts of Reactants and Products
-
- Moles to particles → use avogadro’s number
- Moles to mass (grams) → use molar mass from periodic table
- Moles to Volume (liters) → use 22.4 liters/mol but only for gasses at standard temp and pressure
Calculating Masses of Reactants and Products in Reactions
- Balance the equation for the reaction
- Convert the known masses of reactant or product to moles
- Use balanced equation to set up mole ratios
- Use the mole ratios to calculate the number of moles of desired reactant or product.
- If required, convert moles back to grams
The Limiting Reactant
-
Limiting Reactant: the one that is consumed first and thus limits the amount of product
- You know you have a limiting reactant problem anytime you are given amounts of both reactants
- The reactant that is limiting will make the least amount of product
-
Theoretical yield: The amount of a product formed when the limiting reactant is completely consumed
- What you should have gotten if everything was perfect
-
Actual yield: what you actually get from a reaction
- AP exam will never give you the theoretical yield → will always have to calculate it
- Given mass of reactant
- Write balanced equation
- Process: mass of reactant given x (grams of product/grams of reactant from balanced equation
- Given mass of reactant
Determination of Limiting Reactant Using Reactant Quantities
- Balance the equation
- Do two stoichiometry problems
- Figure out how much product each reactant makes
- The one that makes the least is the limiting reagent (the other is the excess reagent)
- The lesser amount of product is the true amount made